376. If x y z=6, xy yz zx=11, xyz=6 then find x/yz y/zx z/xy (Code 376) video
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376. If x+y+z=6, xy+yz+zx=11, xyz=6 then find x/yz+y/zx+z/xy (Code 376)
If x+y+z = 11, xy+yz+zx = –6 and x^3 + y^3 + z^3 = 1604, then the value of xyz is:
If x+y+z = 6 and xy+yz+zx = 11 and xyz = 6 is given find the value of `x^3+y^3+z^3`.
If x+y+z = 6 and xy+yz+zx = 11 and xyz = 6 is given find the value of `x^3+y^3+z^3`.
If xy+x+y=13, yz+y+z=41 and zx+z+x=11, find the sum of the possible values of xyz.
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Simplify `((x-y)/z+(y-z)/x+(z-x)/y)(z/(x-y)+x/(y-z)+y/(z-x))` if `x+y+z=0`
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