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In figure PS is the bisector of ∠QPR of ΔPQR prove that QS/SR=PQ/PR #triangle #class10
In triangle PQR, angle P= 120°, PS is perpendicular to QR, PQ+QS= SR, then Find angle Q......
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5. PS is the perpendicular bisector of QR and QR is the perpendicular bisector of PS. If PQ = 2x + …
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In Δ PQR, S is a point on the side QR such that PS is the bisector of ∠QPR. If PQ = 12 cm, QS = 3 cm
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