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½ (Li₃(⅓) — Li₃(-⅓)) — ¼ Li₃(¾) — Li₃(-½) = ⁷⁄₆ ζ(3) — ½ (ln2)³ + ½ ln3 (ln2)² — ¹⁄₁₂ ln3 π²

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Let γ∈R be such that the lines L_1 ∶ (x+11)/1=(y+21)/2=(z+29)/3 and L_2 ∶ (x+16)/3=(y+11)/2


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